What are the solutions to the equation (5z+1)^2+9=0 ?

The solutions to the equation (5z+1)^2+9=0 are z=-1/5+i 3/5 ,z=-1/5-i 3/5

Find the zeros of (5z+1)^2+9=0

The zeros of (5z+1)^2+9=0 are z=-1/5+i 3/5 ,z=-1/5-i 3/5

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(5 z + 1)^{2} + 9 = 0

z = - \frac{1}{5} + i \frac{3}{5}, z = - \frac{1}{5} - i \frac{3}{5}

Solution steps

(5 z + 1)^{2} + 9 = 0

Move

9

to the right side

(5 z + 1)^{2} = - 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 z + 1 = - 9 : z = - \frac{1}{5} + i \frac{3}{5}

Solve

5 z + 1 = - - 9 : z = - \frac{1}{5} - i \frac{3}{5}

The solutions to the quadratic equation are:

z = - \frac{1}{5} + i \frac{3}{5}, z = - \frac{1}{5} - i \frac{3}{5}

(2 y)^{\frac{1}{3}}

6 x^{2} + 16 x + 24

2 u + 5 < 17

∣ 3 x ∣ + 3 = 27

5 = \frac{k}{2}

What are the solutions to the equation (5z+1)^2+9=0 ?
The solutions to the equation (5z+1)^2+9=0 are z=-1/5+i 3/5 ,z=-1/5-i 3/5
Find the zeros of (5z+1)^2+9=0
The zeros of (5z+1)^2+9=0 are z=-1/5+i 3/5 ,z=-1/5-i 3/5