What are the solutions to the equation 0=x^2+16 ?

The solutions to the equation 0=x^2+16 are x=4i,x=-4i

Find the zeros of 0=x^2+16

The zeros of 0=x^2+16 are x=4i,x=-4i

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0 = x^{2} + 16

x = 4 i, x = - 4 i

Solution steps

0 = x^{2} + 16

Switch sides

x^{2} + 16 = 0

Move

16

to the right side

x^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 16, x = - - 16

- 16 = 4 i

- - 16 = - 4 i

x = 4 i, x = - 4 i

418

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- 4 x \geq 0

\frac{π}{2} \cdot 4

(x^{\frac{1}{2}} y^{- \frac{2}{3}})^{- 6}

What are the solutions to the equation 0=x^2+16 ?
The solutions to the equation 0=x^2+16 are x=4i,x=-4i
Find the zeros of 0=x^2+16
The zeros of 0=x^2+16 are x=4i,x=-4i