What is the domain of f(n)=(n^2-12n+36)/(108-3n^2) ?

The domain of f(n)=(n^2-12n+36)/(108-3n^2) is n 6

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domain of f(n)=(n^2-12n+36)/(108-3n^2)

domain

f (n) = \frac{n ^{2} - 12 n + 36}{108 - 3 n ^{2}}

n < - 6 or - 6 < n < 6 or n > 6

Interval Notation

(- \infty, - 6) \cup (- 6, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

n = 6, n = - 6

The function domain

n < - 6 or - 6 < n < 6 or n > 6

y^{2} + 6 y = 40

8 \cdot (- \frac{7}{2})

0.5 \leq \frac{y}{8}

- x^{2} + 8 x = x^{2} - 4 x

4 n^{3} + 8 n^{2} + 5 n + 1

What is the domain of f(n)=(n^2-12n+36)/(108-3n^2) ?
The domain of f(n)=(n^2-12n+36)/(108-3n^2) is n<-6\lor-6<n<6\lor n>6