What are the solutions to the equation z^2+7z-8=0 ?

The solutions to the equation z^2+7z-8=0 are z=1,z=-8

Find the zeros of z^2+7z-8=0

The zeros of z^2+7z-8=0 are z=1,z=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

z^{2} + 7 z - 8 = 0

z = 1, z = - 8

Solution steps

z^{2} + 7 z - 8 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 8) = 9

z_{1, 2} = \frac{- 7 \pm 9}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 7 + 9}{2 \cdot 1}, z_{2} = \frac{- 7 - 9}{2 \cdot 1}

z = \frac{- 7 + 9}{2 \cdot 1} : 1

z = \frac{- 7 - 9}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

z = 1, z = - 8

4 - (- 2)

\frac{5 k ^{2}}{( 10 k + 1 ) ( 3 k - 7 )} + \frac{7 k}{( 4 k + 5 ) ( 10 k + 1 )}

8 x y - 18 x^{2}

11 + 3 x - 7 = 6 x + 5 - 3 x

x - 8 \leq - 2

What are the solutions to the equation z^2+7z-8=0 ?
The solutions to the equation z^2+7z-8=0 are z=1,z=-8
Find the zeros of z^2+7z-8=0
The zeros of z^2+7z-8=0 are z=1,z=-8