What are the solutions to the equation y^2-8y-7=0 ?

The solutions to the equation y^2-8y-7=0 are y=4+sqrt(23),y=4-sqrt(23)

Find the zeros of y^2-8y-7=0

The zeros of y^2-8y-7=0 are y=4+sqrt(23),y=4-sqrt(23)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} - 8 y - 7 = 0

y = 4 + 23, y = 4 - 23

Decimal Notation

y = 8.79583 \dots, y = - 0.79583 \dots

Solution steps

y^{2} - 8 y - 7 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 7) = 223

y_{1, 2} = \frac{- ( - 8 ) \pm 2 23}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 2 23}{2 \cdot 1}, y_{2} = \frac{- ( - 8 ) - 2 23}{2 \cdot 1}

y = \frac{- ( - 8 ) + 2 23}{2 \cdot 1} : 4 + 23

y = \frac{- ( - 8 ) - 2 23}{2 \cdot 1} : 4 - 23

The solutions to the quadratic equation are:

y = 4 + 23, y = 4 - 23

40 - 100 m

x^{2} + 10 x + 39 = 23

\frac{27}{12}

3 n^{3} + 12 n^{2}

\frac{7}{24} - \frac{1}{24}

What are the solutions to the equation y^2-8y-7=0 ?
The solutions to the equation y^2-8y-7=0 are y=4+sqrt(23),y=4-sqrt(23)
Find the zeros of y^2-8y-7=0
The zeros of y^2-8y-7=0 are y=4+sqrt(23),y=4-sqrt(23)