What are the solutions to the equation 2y^2=2piy ?

The solutions to the equation 2y^2=2piy are y=0,y=pi

Find the zeros of 2y^2=2piy

The zeros of 2y^2=2piy are y=0,y=pi

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2 y^{2} = 2 π y

y = 0, y = π

Decimal Notation

y = 0, y = 3.14159 \dots

Solution steps

2 y^{2} = 2 π y

Move

2 π y

to the left side

2 y^{2} - 2 π y = 0

Factor

2 y^{2} - 2 π y : 2 y (y - π)

2 y (y - π) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or y - π = 0

Solve

y - π = 0 : y = π

The solutions to the quadratic equation are:

y = 0, y = π

m^{3} + 6 m^{2} n + 9 m n^{2}

b - 2 = 6

\frac{3 x}{5} - \frac{2 x}{3} = 1

9 x - 7 = - 34

- 9 x + 8 \leq - 8 (x - 1)

What are the solutions to the equation 2y^2=2piy ?
The solutions to the equation 2y^2=2piy are y=0,y=pi
Find the zeros of 2y^2=2piy
The zeros of 2y^2=2piy are y=0,y=pi