What are the solutions to the equation 7x^2-3x-8=0 ?

The solutions to the equation 7x^2-3x-8=0 are x=(3+sqrt(233))/(14),x=(3-sqrt(233))/(14)

Find the zeros of 7x^2-3x-8=0

The zeros of 7x^2-3x-8=0 are x=(3+sqrt(233))/(14),x=(3-sqrt(233))/(14)

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7 x^{2} - 3 x - 8 = 0

x = \frac{3 + 233}{14}, x = \frac{3 - 233}{14}

Decimal Notation

x = 1.30459 \dots, x = - 0.87602 \dots

Solution steps

7 x^{2} - 3 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 7 ( - 8 )}{2 \cdot 7}

(- 3)^{2} - 4 \cdot 7 (- 8) = 233

x_{1, 2} = \frac{- ( - 3 ) \pm 233}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 233}{2 \cdot 7}, x_{2} = \frac{- ( - 3 ) - 233}{2 \cdot 7}

x = \frac{- ( - 3 ) + 233}{2 \cdot 7} : \frac{3 + 233}{14}

x = \frac{- ( - 3 ) - 233}{2 \cdot 7} : \frac{3 - 233}{14}

The solutions to the quadratic equation are:

x = \frac{3 + 233}{14}, x = \frac{3 - 233}{14}

x^{2} + x + 1

\frac{( 3 X - 5 )}{X - 1} \geq \frac{1}{2}

- 4 (3 t - 9) \geq 8 (- 8 - t)

\frac{b}{15.6} = 11.6

y^{2} + 14 y + 33 = 0

What are the solutions to the equation 7x^2-3x-8=0 ?
The solutions to the equation 7x^2-3x-8=0 are x=(3+sqrt(233))/(14),x=(3-sqrt(233))/(14)
Find the zeros of 7x^2-3x-8=0
The zeros of 7x^2-3x-8=0 are x=(3+sqrt(233))/(14),x=(3-sqrt(233))/(14)