What are the solutions to the equation 4b^2+2=326 ?

The solutions to the equation 4b^2+2=326 are b=9,b=-9

Find the zeros of 4b^2+2=326

The zeros of 4b^2+2=326 are b=9,b=-9

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4 b^{2} + 2 = 326

b = 9, b = - 9

Solution steps

4 b^{2} + 2 = 326

Move

2

to the right side

4 b^{2} = 324

Divide both sides by

4

b^{2} = 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 81, b = - 81

81 = 9

- 81 = - 9

b = 9, b = - 9

10 x + 18 < - 2

\frac{d ^{14}}{d ^{17}}

lo g_{6} (3) - lo g_{6} (18)

r^{2} + 9 = 0

\frac{x - 3}{3 x + 7} \leq 3

What are the solutions to the equation 4b^2+2=326 ?
The solutions to the equation 4b^2+2=326 are b=9,b=-9
Find the zeros of 4b^2+2=326
The zeros of 4b^2+2=326 are b=9,b=-9