What are the solutions to the equation -x^2+25=0 ?

The solutions to the equation -x^2+25=0 are x=5,x=-5

Find the zeros of -x^2+25=0

The zeros of -x^2+25=0 are x=5,x=-5

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- x^{2} + 25 = 0

x = 5, x = - 5

Solution steps

- x^{2} + 25 = 0

Move

25

to the right side

- x^{2} = - 25

Divide both sides by

- 1

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

\frac{0.8}{2 ^{6}}

lo g_{3} ((x - 1) (2 - 3 x)) < 2

\frac{( ( x + h ) + 6 ) - ( x + 6 )}{h}

- \frac{2}{3} - \frac{2}{3}

\frac{\frac{5}{3}}{2}

What are the solutions to the equation -x^2+25=0 ?
The solutions to the equation -x^2+25=0 are x=5,x=-5
Find the zeros of -x^2+25=0
The zeros of -x^2+25=0 are x=5,x=-5