What are the solutions to the equation 3(x+8)^2-20=28 ?

The solutions to the equation 3(x+8)^2-20=28 are x=-4,x=-12

Find the zeros of 3(x+8)^2-20=28

The zeros of 3(x+8)^2-20=28 are x=-4,x=-12

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3 (x + 8)^{2} - 20 = 28

x = - 4, x = - 12

Solution steps

3 (x + 8)^{2} - 20 = 28

Move

20

to the right side

3 (x + 8)^{2} = 48

Divide both sides by

3

(x + 8)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 8 = 16 : x = - 4

Solve

x + 8 = - 16 : x = - 12

The solutions to the quadratic equation are:

x = - 4, x = - 12

(64 x)^{\frac{1}{6}}

y - 3 > 10

\frac{9}{5} + \frac{6}{9}

2 r^{3} + 2 r^{2} - 40 r

0. 7^{4}

What are the solutions to the equation 3(x+8)^2-20=28 ?
The solutions to the equation 3(x+8)^2-20=28 are x=-4,x=-12
Find the zeros of 3(x+8)^2-20=28
The zeros of 3(x+8)^2-20=28 are x=-4,x=-12