What are the solutions to the equation 0=-3x^2+14xx-8 ?

The solutions to the equation 0=-3x^2+14xx-8 are x=(2sqrt(2))/(sqrt(11)),x=-(2sqrt(2))/(sqrt(11))

Find the zeros of 0=-3x^2+14xx-8

The zeros of 0=-3x^2+14xx-8 are x=(2sqrt(2))/(sqrt(11)),x=-(2sqrt(2))/(sqrt(11))

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0 = - 3 x^{2} + 14 xx - 8

x = \frac{2 2}{11}, x = - \frac{2 2}{11}

Decimal Notation

x = 0.85280 \dots, x = - 0.85280 \dots

Solution steps

0 = - 3 x^{2} + 14 xx - 8

Expand

- 3 x^{2} + 14 xx - 8 : 11 x^{2} - 8

0 = 11 x^{2} - 8

Switch sides

11 x^{2} - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 11 ( - 8 )}{2 \cdot 11}

0^{2} - 4 \cdot 11 (- 8) = 422

x_{1, 2} = \frac{- 0 \pm 4 22}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- 0 + 4 22}{2 \cdot 11}, x_{2} = \frac{- 0 - 4 22}{2 \cdot 11}

x = \frac{- 0 + 4 22}{2 \cdot 11} : \frac{2 2}{11}

x = \frac{- 0 - 4 22}{2 \cdot 11} : - \frac{2 2}{11}

The solutions to the quadratic equation are:

x = \frac{2 2}{11}, x = - \frac{2 2}{11}

x^{2} y + 3 x y

25 - 5 + 45 + 3

\frac{- 2 x}{3} = x + 10

(\frac{5 6 ^{\frac{1}{4}}}{7 ^{\frac{1}{4}}})^{5}

9 x^{2} - 121

What are the solutions to the equation 0=-3x^2+14xx-8 ?
The solutions to the equation 0=-3x^2+14xx-8 are x=(2sqrt(2))/(sqrt(11)),x=-(2sqrt(2))/(sqrt(11))
Find the zeros of 0=-3x^2+14xx-8
The zeros of 0=-3x^2+14xx-8 are x=(2sqrt(2))/(sqrt(11)),x=-(2sqrt(2))/(sqrt(11))