What are the solutions to the equation -3x^2-3x+11=2x ?

The solutions to the equation -3x^2-3x+11=2x are x=-(5+sqrt(157))/6 ,x=(sqrt(157)-5)/6

Find the zeros of -3x^2-3x+11=2x

The zeros of -3x^2-3x+11=2x are x=-(5+sqrt(157))/6 ,x=(sqrt(157)-5)/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{2} - 3 x + 11 = 2 x

x = - \frac{5 + 157}{6}, x = \frac{157 - 5}{6}

Decimal Notation

x = - 2.92166 \dots, x = 1.25499 \dots

Solution steps

- 3 x^{2} - 3 x + 11 = 2 x

Move

2 x

to the left side

- 3 x^{2} - 5 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 3 ) \cdot 11}{2 ( - 3 )}

(- 5)^{2} - 4 (- 3) \cdot 11 = 157

x_{1, 2} = \frac{- ( - 5 ) \pm 157}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 157}{2 ( - 3 )}, x_{2} = \frac{- ( - 5 ) - 157}{2 ( - 3 )}

x = \frac{- ( - 5 ) + 157}{2 ( - 3 )} : - \frac{5 + 157}{6}

x = \frac{- ( - 5 ) - 157}{2 ( - 3 )} : \frac{157 - 5}{6}

The solutions to the quadratic equation are:

x = - \frac{5 + 157}{6}, x = \frac{157 - 5}{6}

4^{4}

\frac{( 79 + 7 i )}{6 - 7 i}

9 z^{2} - 24 z + 16

\frac{2 - 5}{1 + 5}

\frac{x ^{2}}{x ^{2}} \cdot \frac{z ^{2}}{y ^{- 2}}

What are the solutions to the equation -3x^2-3x+11=2x ?
The solutions to the equation -3x^2-3x+11=2x are x=-(5+sqrt(157))/6 ,x=(sqrt(157)-5)/6
Find the zeros of -3x^2-3x+11=2x
The zeros of -3x^2-3x+11=2x are x=-(5+sqrt(157))/6 ,x=(sqrt(157)-5)/6