What are the solutions to the equation -x^2+12-8x=-3 ?

The solutions to the equation -x^2+12-8x=-3 are x=-4-sqrt(31),x=sqrt(31)-4

Find the zeros of -x^2+12-8x=-3

The zeros of -x^2+12-8x=-3 are x=-4-sqrt(31),x=sqrt(31)-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} + 12 - 8 x = - 3

x = - 4 - 31, x = 31 - 4

Decimal Notation

x = - 9.56776 \dots, x = 1.56776 \dots

Solution steps

- x^{2} + 12 - 8 x = - 3

Move

3

to the left side

- x^{2} - 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 1 ) \cdot 15}{2 ( - 1 )}

(- 8)^{2} - 4 (- 1) \cdot 15 = 231

x_{1, 2} = \frac{- ( - 8 ) \pm 2 31}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 31}{2 ( - 1 )}, x_{2} = \frac{- ( - 8 ) - 2 31}{2 ( - 1 )}

x = \frac{- ( - 8 ) + 2 31}{2 ( - 1 )} : - 4 - 31

x = \frac{- ( - 8 ) - 2 31}{2 ( - 1 )} : 31 - 4

The solutions to the quadratic equation are:

x = - 4 - 31, x = 31 - 4

x^{3} + x - 10

3 x^{2} = 6 x - 9

\frac{y - x ( \frac{x}{y} )}{y ^{2}}

x^{3} + 16 x^{2} + 28 x

25 x^{2} - 10 x y + y^{2}

What are the solutions to the equation -x^2+12-8x=-3 ?
The solutions to the equation -x^2+12-8x=-3 are x=-4-sqrt(31),x=sqrt(31)-4
Find the zeros of -x^2+12-8x=-3
The zeros of -x^2+12-8x=-3 are x=-4-sqrt(31),x=sqrt(31)-4