What are the solutions to the equation 9-2x^2=0 ?

The solutions to the equation 9-2x^2=0 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

Find the zeros of 9-2x^2=0

The zeros of 9-2x^2=0 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

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9 - 2 x^{2} = 0

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 2.12132 \dots, x = - 2.12132 \dots

Solution steps

9 - 2 x^{2} = 0

Move

9

to the right side

- 2 x^{2} = - 9

Divide both sides by

- 2

x^{2} = \frac{9}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{9}{2}, x = - \frac{9}{2}

\frac{9}{2} = \frac{3}{2}

- \frac{9}{2} = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

4 x^{4} + 12 x - 4 x^{3} - 12 x^{2}

\frac{3}{3 + 7 i}

5 j - 4 j = 17

∣ x + 10 ∣ \geq 14

- 2 x + 5 \leq 3 x + 3

What are the solutions to the equation 9-2x^2=0 ?
The solutions to the equation 9-2x^2=0 are x= 3/(sqrt(2)),x=-3/(sqrt(2))
Find the zeros of 9-2x^2=0
The zeros of 9-2x^2=0 are x= 3/(sqrt(2)),x=-3/(sqrt(2))