What is factor 28x+49x^2+4 ?

The solution to factor 28x+49x^2+4 is (7x+2)^2

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factor 28x+49x^2+4

factor

28 x + 49 x^{2} + 4

(7 x + 2)^{2}

Solution steps

28 x + 49 x^{2} + 4

Write in the standard form

= 49 x^{2} + 28 x + 4

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

49 x^{2} = (7 x)^{2}

4 = 2^{2}

28 x = 2 \cdot 7 x \cdot 2

= (7 x)^{2} + 2 \cdot 7 x \cdot 2 + 2^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(7 x)^{2} + 2 \cdot 7 x \cdot 2 + 2^{2} = (7 x + 2)^{2}

= (7 x + 2)^{2}

\frac{7}{3} + \frac{2}{3}

x^{4} - 32 x^{2} - 144 > 0

n^{2} = 6 \cdot 1 0^{7}

6^{2} + 8^{2}