What is 3(x+2)(-x+7)(e^x-e)>= 0 ?

The solution to 3(x+2)(-x+7)(e^x-e)>= 0 is x<=-2\lor 1<= x<= 7

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3(x+2)(-x+7)(e^x-e)>= 0

3 (x + 2) (- x + 7) (e^{x} - e) \geq 0

x \leq - 2 or 1 \leq x \leq 7

Interval Notation

(- \infty, - 2] \cup [1, 7]

Solution steps

3 (x + 2) (- x + 7) (e^{x} - e) \geq 0

Divide both sides by

3

\frac{3 ( x + 2 ) ( - x + 7 ) ( e ^{x} - e )}{3} \geq \frac{0}{3}

Simplify

(x + 2) (- x + 7) (- e + e^{x}) \geq 0

Identify the intervals

x \leq - 2 or 1 \leq x \leq 7

u^{2} - v^{2}

y^{2} - 36 x^{6}

400 = 3.915 (1.106) x

2 x^{2} + 2 x > 4

y, y^{2} = x^{3} - 4 x

What is 3(x+2)(-x+7)(e^x-e)>= 0 ?
The solution to 3(x+2)(-x+7)(e^x-e)>= 0 is x<=-2\lor 1<= x<= 7