What is (s^{-1}t^{23}u^{-6})/(s^{-8)tu} ?

The solution to (s^{-1}t^{23}u^{-6})/(s^{-8)tu} is (s^7t^{22})/(u^7)

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simplify (s^{-1}t^{23}u^{-6})/(s^{-8)tu}

simplify

\frac{s ^{- 1} t ^{23} u ^{- 6}}{s ^{- 8} t u}

\frac{s ^{7} t ^{22}}{u ^{7}}

Solution steps

\frac{s ^{- 1} t ^{23} u ^{- 6}}{s ^{- 8} t u}

Simplify

\frac{s ^{- 1}}{s ^{- 8}} : s^{7}

= \frac{s ^{7} t ^{23} u ^{- 6}}{t u}

Simplify

\frac{t ^{23}}{t} : t^{22}

= \frac{s ^{7} t ^{22} u ^{- 6}}{u}

Simplify

\frac{u ^{- 6}}{u} : \frac{1}{u ^{7}}

= \frac{s ^{7} t ^{22}}{u ^{7}}

lo g_{5} (\frac{1}{25})

\frac{10 + 2 x}{3} = 4

- 10 x = 50

\frac{4 ^{11}}{4 ^{- 8}}

\frac{7}{8} x \frac{- 3}{8} x = \frac{1}{5} + \frac{3}{10}

What is (s^{-1}t^{23}u^{-6})/(s^{-8)tu} ?
The solution to (s^{-1}t^{23}u^{-6})/(s^{-8)tu} is (s^7t^{22})/(u^7)