What are the solutions to the equation 6x^2-12x-90=152 ?

The solutions to the equation 6x^2-12x-90=152 are x=(3+2sqrt(93))/3 ,x=(3-2sqrt(93))/3

Find the zeros of 6x^2-12x-90=152

The zeros of 6x^2-12x-90=152 are x=(3+2sqrt(93))/3 ,x=(3-2sqrt(93))/3

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6 x^{2} - 12 x - 90 = 152

x = \frac{3 + 2 93}{3}, x = \frac{3 - 2 93}{3}

Decimal Notation

x = 7.42910 \dots, x = - 5.42910 \dots

Solution steps

6 x^{2} - 12 x - 90 = 152

Move

152

to the left side

6 x^{2} - 12 x - 242 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 ( - 242 )}{2 \cdot 6}

(- 12)^{2} - 4 \cdot 6 (- 242) = 893

x_{1, 2} = \frac{- ( - 12 ) \pm 8 93}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8 93}{2 \cdot 6}, x_{2} = \frac{- ( - 12 ) - 8 93}{2 \cdot 6}

x = \frac{- ( - 12 ) + 8 93}{2 \cdot 6} : \frac{3 + 2 93}{3}

x = \frac{- ( - 12 ) - 8 93}{2 \cdot 6} : \frac{3 - 2 93}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 2 93}{3}, x = \frac{3 - 2 93}{3}

\frac{x + 1}{1 - x} + \frac{x - 1}{x} < 2

2 x + \frac{5}{3} > \frac{2}{5} x - 1

64 - - 289

5 x + 1 = 3 x - 4

x^{2} + 4 x + 3 \leq 0

What are the solutions to the equation 6x^2-12x-90=152 ?
The solutions to the equation 6x^2-12x-90=152 are x=(3+2sqrt(93))/3 ,x=(3-2sqrt(93))/3
Find the zeros of 6x^2-12x-90=152
The zeros of 6x^2-12x-90=152 are x=(3+2sqrt(93))/3 ,x=(3-2sqrt(93))/3