What are the solutions to the equation c^2=3^2+4^2 ?

The solutions to the equation c^2=3^2+4^2 are c=5,c=-5

Find the zeros of c^2=3^2+4^2

The zeros of c^2=3^2+4^2 are c=5,c=-5

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c^{2} = 3^{2} + 4^{2}

c = 5, c = - 5

Solution steps

c^{2} = 3^{2} + 4^{2}

Simplify

3^{2} + 4^{2} : 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 25, c = - 25

25 = 5

- 25 = - 5

c = 5, c = - 5

x^{3} - 4 x^{2} + 3 x \leq 0

\frac{9 z ^{3}}{16 x y} \cdot \frac{4 x}{27 z ^{3}}

3 \frac{x}{2} + 1 + \frac{3}{2} = 4

\frac{2 ( 4 - 1 ) ^{3}}{12 ( 10 ) ^{2}}

17 < - 3 x

What are the solutions to the equation c^2=3^2+4^2 ?
The solutions to the equation c^2=3^2+4^2 are c=5,c=-5
Find the zeros of c^2=3^2+4^2
The zeros of c^2=3^2+4^2 are c=5,c=-5