What are the solutions to the equation 3x^2-x+1=0 ?

The solutions to the equation 3x^2-x+1=0 are x= 1/6+i(sqrt(11))/6 ,x= 1/6-i(sqrt(11))/6

Find the zeros of 3x^2-x+1=0

The zeros of 3x^2-x+1=0 are x= 1/6+i(sqrt(11))/6 ,x= 1/6-i(sqrt(11))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - x + 1 = 0

x = \frac{1}{6} + i \frac{11}{6}, x = \frac{1}{6} - i \frac{11}{6}

Solution steps

3 x^{2} - x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

Simplify

(- 1)^{2} - 4 \cdot 3 \cdot 1 : 11 i

x_{1, 2} = \frac{- ( - 1 ) \pm 11 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 11 i}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 11 i}{2 \cdot 3}

x = \frac{- ( - 1 ) + 11 i}{2 \cdot 3} : \frac{1}{6} + i \frac{11}{6}

x = \frac{- ( - 1 ) - 11 i}{2 \cdot 3} : \frac{1}{6} - i \frac{11}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} + i \frac{11}{6}, x = \frac{1}{6} - i \frac{11}{6}

\frac{6}{5} x = 30

x - 4

3 \times 1 0^{5}

\frac{34}{1.69} = \frac{3}{1.69} - \frac{68}{1. 3 ^{3}} (0.02)

7 = x - 5

What are the solutions to the equation 3x^2-x+1=0 ?
The solutions to the equation 3x^2-x+1=0 are x= 1/6+i(sqrt(11))/6 ,x= 1/6-i(sqrt(11))/6
Find the zeros of 3x^2-x+1=0
The zeros of 3x^2-x+1=0 are x= 1/6+i(sqrt(11))/6 ,x= 1/6-i(sqrt(11))/6