What are the solutions to the equation (2x+3)^2=10 ?

The solutions to the equation (2x+3)^2=10 are x=(sqrt(10)-3)/2 ,x=(-sqrt(10)-3)/2

Find the zeros of (2x+3)^2=10

The zeros of (2x+3)^2=10 are x=(sqrt(10)-3)/2 ,x=(-sqrt(10)-3)/2

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(2 x + 3)^{2} = 10

x = \frac{10 - 3}{2}, x = \frac{- 10 - 3}{2}

Decimal

x = 0.08113 \dots, x = - 3.08113 \dots

Solution steps

(2 x + 3)^{2} = 10

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 3 = 10 : x = \frac{10 - 3}{2}

Solve

2 x + 3 = - 10 : x = \frac{- 10 - 3}{2}

The solutions to the quadratic equation are:

x = \frac{10 - 3}{2}, x = \frac{- 10 - 3}{2}

84

x^{2} = \frac{16}{2} x - \frac{4}{2}

\frac{- 8 + 4}{2 + 5}

0 = - 2 x + 2

- 8 > \frac{k}{- 0.2}

What are the solutions to the equation (2x+3)^2=10 ?
The solutions to the equation (2x+3)^2=10 are x=(sqrt(10)-3)/2 ,x=(-sqrt(10)-3)/2
Find the zeros of (2x+3)^2=10
The zeros of (2x+3)^2=10 are x=(sqrt(10)-3)/2 ,x=(-sqrt(10)-3)/2