What are the solutions to the equation 2x^2-17x=-30 ?

The solutions to the equation 2x^2-17x=-30 are x=6,x= 5/2

Find the zeros of 2x^2-17x=-30

The zeros of 2x^2-17x=-30 are x=6,x= 5/2

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2 x^{2} - 17 x = - 30

x = 6, x = \frac{5}{2}

Decimal

x = 6, x = 2.5

Solution steps

2 x^{2} - 17 x = - 30

Move

30

to the left side

2 x^{2} - 17 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 2 \cdot 30}{2 \cdot 2}

(- 17)^{2} - 4 \cdot 2 \cdot 30 = 7

x_{1, 2} = \frac{- ( - 17 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 17 ) - 7}{2 \cdot 2}

x = \frac{- ( - 17 ) + 7}{2 \cdot 2} : 6

x = \frac{- ( - 17 ) - 7}{2 \cdot 2} : \frac{5}{2}

The solutions to the quadratic equation are:

x = 6, x = \frac{5}{2}

- 6 y = - 24

185

\frac{\frac{2}{x + y}}{3}

∣ x + 3 ∣ < 8

0.5 = p^{3} + 3 p^{2} (1 - p) + 3 p (1 - p)^{2} + (1 - p)^{3}

What are the solutions to the equation 2x^2-17x=-30 ?
The solutions to the equation 2x^2-17x=-30 are x=6,x= 5/2
Find the zeros of 2x^2-17x=-30
The zeros of 2x^2-17x=-30 are x=6,x= 5/2