What is factor a^7b^8-a^5b^4+a^4b^6-a^4b^4 ?

The solution to factor a^7b^8-a^5b^4+a^4b^6-a^4b^4 is a^4b^4(a^3b^4-a+b^2-1)

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factor a^7b^8-a^5b^4+a^4b^6-a^4b^4

factor

a^{7} b^{8} - a^{5} b^{4} + a^{4} b^{6} - a^{4} b^{4}

a^{4} b^{4} (a^{3} b^{4} - a + b^{2} - 1)

Solution steps

a^{7} b^{8} - a^{5} b^{4} + a^{4} b^{6} - a^{4} b^{4}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

a^{7} b^{8} = a^{4} a^{3} b^{4} b^{4}, a^{5} b^{4} = a^{4} a b^{4}, a^{4} b^{6} = a^{4} b^{4} b^{2}

= a^{4} a^{3} b^{4} b^{4} - a^{4} a b^{4} + a^{4} b^{4} b^{2} - a^{4} b^{4}

Factor out common term

a^{4} b^{4}

= a^{4} b^{4} (a^{3} b^{4} - a + b^{2} - 1)

ln (2) + ln (3)

15 x^{2} + 4 x - 3 = 0

x^{2} + 25 x

\frac{1}{1 + e ^{- 2}}

4.6 (x + 3) - 1 = - 10.2

What is factor a^7b^8-a^5b^4+a^4b^6-a^4b^4 ?
The solution to factor a^7b^8-a^5b^4+a^4b^6-a^4b^4 is a^4b^4(a^3b^4-a+b^2-1)