What is ((x+1))/(x+2)>= (x-4)/(2x-3) ?

The solution to ((x+1))/(x+2)>= (x-4)/(2x-3) is x 3/2

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((x+1))/(x+2)>= (x-4)/(2x-3)

\frac{( x + 1 )}{x + 2} \geq \frac{x - 4}{2 x - 3}

x < - 2 or x > \frac{3}{2}

Interval Notation

(- \infty, - 2) \cup (\frac{3}{2}, \infty)

Decimal Notation

x < - 2 or x > 1.5

Solution steps

\frac{x + 1}{x + 2} \geq \frac{x - 4}{2 x - 3}

Rewrite in standard form

\frac{x ^{2} + x + 5}{( x + 2 ) ( 2 x - 3 )} \geq 0

Identify the intervals

x < - 2 or x > \frac{3}{2}

36 + 4 x^{2} + \frac{1}{9} x^{4}

p^{2} + 4 p - 12 = 0

y (2 + y) - y - 2

(\frac{0.03}{1})^{\frac{1}{2}} \cdot 0.5 \cdot 109

\frac{x + 5}{x - 7} \leq 1

What is ((x+1))/(x+2)>= (x-4)/(2x-3) ?
The solution to ((x+1))/(x+2)>= (x-4)/(2x-3) is x<-2\lor x> 3/2