What are the solutions to the equation x^2-7x+4=0 ?

The solutions to the equation x^2-7x+4=0 are x=(7+sqrt(33))/2 ,x=(7-sqrt(33))/2

Find the zeros of x^2-7x+4=0

The zeros of x^2-7x+4=0 are x=(7+sqrt(33))/2 ,x=(7-sqrt(33))/2

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x^{2} - 7 x + 4 = 0

x = \frac{7 + 33}{2}, x = \frac{7 - 33}{2}

Decimal Notation

x = 6.37228 \dots, x = 0.62771 \dots

Solution steps

x^{2} - 7 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 4 = 33

x_{1, 2} = \frac{- ( - 7 ) \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 33}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 33}{2 \cdot 1}

x = \frac{- ( - 7 ) + 33}{2 \cdot 1} : \frac{7 + 33}{2}

x = \frac{- ( - 7 ) - 33}{2 \cdot 1} : \frac{7 - 33}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 33}{2}, x = \frac{7 - 33}{2}

\frac{20 ( 5 + 3 ( 13 ) )}{1 + 0.04 ( 13 )}

x y^{3} - x^{3} y

12 x^{2} - 11 x - 5

x^{2} + 2 x = 5

16 m^{2} - 25 n^{2}

What are the solutions to the equation x^2-7x+4=0 ?
The solutions to the equation x^2-7x+4=0 are x=(7+sqrt(33))/2 ,x=(7-sqrt(33))/2
Find the zeros of x^2-7x+4=0
The zeros of x^2-7x+4=0 are x=(7+sqrt(33))/2 ,x=(7-sqrt(33))/2