What is factor 64x^3-y^6 ?

The solution to factor 64x^3-y^6 is (4x-y^2)(16x^2+4xy^2+y^4)

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factor 64x^3-y^6

factor

64 x^{3} - y^{6}

(4 x - y^{2}) (16 x^{2} + 4 x y^{2} + y^{4})

Solution steps

64 x^{3} - y^{6}

Apply exponent rules

= (4 x)^{3} - (y^{2})^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(4 x)^{3} - (y^{2})^{3} = (4 x - y^{2}) ((4 x)^{2} + 4 x y^{2} + (y^{2})^{2})

= (4 x - y^{2}) ((4 x)^{2} + 4 x y^{2} + (y^{2})^{2})

Simplify

(4 x)^{2} + 4 x y^{2} + (y^{2})^{2} : 16 x^{2} + 4 x y^{2} + y^{4}

= (4 x - y^{2}) (16 x^{2} + 4 x y^{2} + y^{4})

\frac{q ^{6} ( - r ) ^{7}}{q ^{10} r ^{5}}

2^{l o g_{2} (6)}

100 f - 75 = 50 f + 75

- 5 < x - 4 < 2 - x

\frac{4}{3} + \frac{2}{7} - \frac{7}{21}

What is factor 64x^3-y^6 ?
The solution to factor 64x^3-y^6 is (4x-y^2)(16x^2+4xy^2+y^4)