What are the solutions to the equation 11x^2+4x+12=0 ?

The solutions to the equation 11x^2+4x+12=0 are x=-2/11+i(8sqrt(2))/(11),x=-2/11-i(8sqrt(2))/(11)

Find the zeros of 11x^2+4x+12=0

The zeros of 11x^2+4x+12=0 are x=-2/11+i(8sqrt(2))/(11),x=-2/11-i(8sqrt(2))/(11)

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11 x^{2} + 4 x + 12 = 0

x = - \frac{2}{11} + i \frac{8 2}{11}, x = - \frac{2}{11} - i \frac{8 2}{11}

Solution steps

11 x^{2} + 4 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 11 \cdot 12}{2 \cdot 11}

Simplify

4^{2} - 4 \cdot 11 \cdot 12 : 162 i

x_{1, 2} = \frac{- 4 \pm 16 2 i}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- 4 + 16 2 i}{2 \cdot 11}, x_{2} = \frac{- 4 - 16 2 i}{2 \cdot 11}

x = \frac{- 4 + 16 2 i}{2 \cdot 11} : - \frac{2}{11} + i \frac{8 2}{11}

x = \frac{- 4 - 16 2 i}{2 \cdot 11} : - \frac{2}{11} - i \frac{8 2}{11}

The solutions to the quadratic equation are:

x = - \frac{2}{11} + i \frac{8 2}{11}, x = - \frac{2}{11} - i \frac{8 2}{11}

64 x^{4} - 1

28 ab - 35 a^{2} + 7 a

x^{2} - 9 x + 20

5 x - 6 \leq x - 2

\frac{1}{6} > 0.166667

What are the solutions to the equation 11x^2+4x+12=0 ?
The solutions to the equation 11x^2+4x+12=0 are x=-2/11+i(8sqrt(2))/(11),x=-2/11-i(8sqrt(2))/(11)
Find the zeros of 11x^2+4x+12=0
The zeros of 11x^2+4x+12=0 are x=-2/11+i(8sqrt(2))/(11),x=-2/11-i(8sqrt(2))/(11)