What is (2u^2v^3)^3(3u^3v)^{-2} ?

The solution to (2u^2v^3)^3(3u^3v)^{-2} is (8v^7)/9

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simplify (2u^2v^3)^3(3u^3v)^{-2}

simplify

(2 u^{2} v^{3})^{3} (3 u^{3} v)^{- 2}

\frac{8 v ^{7}}{9}

Solution steps

(2 u^{2} v^{3})^{3} (3 u^{3} v)^{- 2}

Simplify

(2 u^{2} v^{3})^{3} : 8 u^{6} v^{9}

= 8 u^{6} v^{9} (3 u^{3} v)^{- 2}

Simplify

(3 u^{3} v)^{- 2} : \frac{1}{9 u ^{6} v ^{2}}

= 8 u^{6} v^{9} \frac{1}{9 u ^{6} v ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{8 u ^{6} v ^{9} \cdot 1}{9 u ^{6} v ^{2}}

Multiply the numbers:

8 \cdot 1 = 8

= \frac{8 u ^{6} v ^{9}}{9 u ^{6} v ^{2}}

Cancel the common factor:

u^{6}

= \frac{8 v ^{9}}{9 v ^{2}}

Simplify

\frac{v ^{9}}{v ^{2}} : v^{7}

= \frac{8 v ^{7}}{9}

36 - 6 s = 48

2 x^{4} + x^{3} - 8 x^{2} - x + 6

- 2 (\frac{3}{2})

6 = 3 s

(2 x - 1) (x + 5) = 0

What is (2u^2v^3)^3(3u^3v)^{-2} ?
The solution to (2u^2v^3)^3(3u^3v)^{-2} is (8v^7)/9