What are the solutions to the equation 0=-2x^2+7x-3 ?

The solutions to the equation 0=-2x^2+7x-3 are x= 1/2 ,x=3

Find the zeros of 0=-2x^2+7x-3

The zeros of 0=-2x^2+7x-3 are x= 1/2 ,x=3

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0 = - 2 x^{2} + 7 x - 3

x = \frac{1}{2}, x = 3

Decimal Notation

x = 0.5, x = 3

Solution steps

0 = - 2 x^{2} + 7 x - 3

Switch sides

- 2 x^{2} + 7 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 2 ) ( - 3 )}{2 ( - 2 )}

7^{2} - 4 (- 2) (- 3) = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 ( - 2 )}, x_{2} = \frac{- 7 - 5}{2 ( - 2 )}

x = \frac{- 7 + 5}{2 ( - 2 )} : \frac{1}{2}

x = \frac{- 7 - 5}{2 ( - 2 )} : 3

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 3

x^{2} + 3 x - 2 > (x + 2)^{2}

- \frac{1}{2} (2)^{- 1}

4 a^{2} - 432 = 0

(5 q - 30)^{3}

x yz + x^{2} y^{2} z^{2}

What are the solutions to the equation 0=-2x^2+7x-3 ?
The solutions to the equation 0=-2x^2+7x-3 are x= 1/2 ,x=3
Find the zeros of 0=-2x^2+7x-3
The zeros of 0=-2x^2+7x-3 are x= 1/2 ,x=3