What are the solutions to the equation 4m^2+13m=-3 ?

The solutions to the equation 4m^2+13m=-3 are m=-1/4 ,m=-3

Find the zeros of 4m^2+13m=-3

The zeros of 4m^2+13m=-3 are m=-1/4 ,m=-3

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4 m^{2} + 13 m = - 3

m = - \frac{1}{4}, m = - 3

Decimal Notation

m = - 0.25, m = - 3

Solution steps

4 m^{2} + 13 m = - 3

Move

3

to the left side

4 m^{2} + 13 m + 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

1 3^{2} - 4 \cdot 4 \cdot 3 = 11

m_{1, 2} = \frac{- 13 \pm 11}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- 13 + 11}{2 \cdot 4}, m_{2} = \frac{- 13 - 11}{2 \cdot 4}

m = \frac{- 13 + 11}{2 \cdot 4} : - \frac{1}{4}

m = \frac{- 13 - 11}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

m = - \frac{1}{4}, m = - 3

\frac{2 ( 2 )}{2 + 5}

m^{5} - 2 \geq - 3

\frac{2}{2} \cdot \frac{3}{2}

- x^{2} + 2 x - 1

x^{8} - 8 x^{4} + 12

What are the solutions to the equation 4m^2+13m=-3 ?
The solutions to the equation 4m^2+13m=-3 are m=-1/4 ,m=-3
Find the zeros of 4m^2+13m=-3
The zeros of 4m^2+13m=-3 are m=-1/4 ,m=-3