What are the solutions to the equation x^2-12x+16=0 ?

The solutions to the equation x^2-12x+16=0 are x=2(3+sqrt(5)),x=2(3-sqrt(5))

Find the zeros of x^2-12x+16=0

The zeros of x^2-12x+16=0 are x=2(3+sqrt(5)),x=2(3-sqrt(5))

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x^{2} - 12 x + 16 = 0

x = 2 (3 + 5), x = 2 (3 - 5)

Decimal Notation

x = 10.47213 \dots, x = 1.52786 \dots

Solution steps

x^{2} - 12 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 16 = 45

x_{1, 2} = \frac{- ( - 12 ) \pm 4 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 5}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4 5}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4 5}{2 \cdot 1} : 2 (3 + 5)

x = \frac{- ( - 12 ) - 4 5}{2 \cdot 1} : 2 (3 - 5)

The solutions to the quadratic equation are:

x = 2 (3 + 5), x = 2 (3 - 5)

\frac{5}{5 + 6 i}

\frac{4 a ^{2} - 20 a + 25}{25 - 4 a ^{2}}

\frac{14}{4}

x^{2} + 2 x y - 8 y^{2}

4 \cdot 64

What are the solutions to the equation x^2-12x+16=0 ?
The solutions to the equation x^2-12x+16=0 are x=2(3+sqrt(5)),x=2(3-sqrt(5))
Find the zeros of x^2-12x+16=0
The zeros of x^2-12x+16=0 are x=2(3+sqrt(5)),x=2(3-sqrt(5))