What are the solutions to the equation m^2+8m-81=0 ?

The solutions to the equation m^2+8m-81=0 are m=-4+sqrt(97),m=-4-sqrt(97)

Find the zeros of m^2+8m-81=0

The zeros of m^2+8m-81=0 are m=-4+sqrt(97),m=-4-sqrt(97)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} + 8 m - 81 = 0

m = - 4 + 97, m = - 4 - 97

Decimal Notation

m = 5.84885 \dots, m = - 13.84885 \dots

Solution steps

m^{2} + 8 m - 81 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 81 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 81) = 297

m_{1, 2} = \frac{- 8 \pm 2 97}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 8 + 2 97}{2 \cdot 1}, m_{2} = \frac{- 8 - 2 97}{2 \cdot 1}

m = \frac{- 8 + 2 97}{2 \cdot 1} : - 4 + 97

m = \frac{- 8 - 2 97}{2 \cdot 1} : - 4 - 97

The solutions to the quadratic equation are:

m = - 4 + 97, m = - 4 - 97

(7 x - 2)^{2} = 16

2 z + 4 \geq - 4

lo g_{8} (64)

\frac{2 + 3 i}{7}

- \frac{1}{3 ^{2}}

What are the solutions to the equation m^2+8m-81=0 ?
The solutions to the equation m^2+8m-81=0 are m=-4+sqrt(97),m=-4-sqrt(97)
Find the zeros of m^2+8m-81=0
The zeros of m^2+8m-81=0 are m=-4+sqrt(97),m=-4-sqrt(97)