What are the solutions to the equation x^2-0.3x+0.2=0 ?

The solutions to the equation x^2-0.3x+0.2=0 are x= 3/20+i(sqrt(71))/(20),x= 3/20-i(sqrt(71))/(20)

Find the zeros of x^2-0.3x+0.2=0

The zeros of x^2-0.3x+0.2=0 are x= 3/20+i(sqrt(71))/(20),x= 3/20-i(sqrt(71))/(20)

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x^{2} - 0.3 x + 0.2 = 0

x = \frac{3}{20} + i \frac{71}{20}, x = \frac{3}{20} - i \frac{71}{20}

Solution steps

x^{2} - 0.3 x + 0.2 = 0

Multiply both sides by

10

10 x^{2} - 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 10 \cdot 2}{2 \cdot 10}

Simplify

(- 3)^{2} - 4 \cdot 10 \cdot 2 : 71 i

x_{1, 2} = \frac{- ( - 3 ) \pm 71 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 71 i}{2 \cdot 10}, x_{2} = \frac{- ( - 3 ) - 71 i}{2 \cdot 10}

x = \frac{- ( - 3 ) + 71 i}{2 \cdot 10} : \frac{3}{20} + i \frac{71}{20}

x = \frac{- ( - 3 ) - 71 i}{2 \cdot 10} : \frac{3}{20} - i \frac{71}{20}

The solutions to the quadratic equation are:

x = \frac{3}{20} + i \frac{71}{20}, x = \frac{3}{20} - i \frac{71}{20}

2 x^{2} - 98 = 0

3 x^{2} = 144

\frac{∣ 3 x - 3 ∣}{5} = 6

\frac{135 x ^{3}}{49 y ^{4}}

∣ 2 y + 6 ∣ = ∣ 2 y - 4 ∣

What are the solutions to the equation x^2-0.3x+0.2=0 ?
The solutions to the equation x^2-0.3x+0.2=0 are x= 3/20+i(sqrt(71))/(20),x= 3/20-i(sqrt(71))/(20)
Find the zeros of x^2-0.3x+0.2=0
The zeros of x^2-0.3x+0.2=0 are x= 3/20+i(sqrt(71))/(20),x= 3/20-i(sqrt(71))/(20)