What are the solutions to the equation (x-2)(x-8)=-9 ?

The solutions to the equation (x-2)(x-8)=-9 are x=5

Find the zeros of (x-2)(x-8)=-9

The zeros of (x-2)(x-8)=-9 are x=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 2) (x - 8) = - 9

x = 5

Solution steps

(x - 2) (x - 8) = - 9

Expand

(x - 2) (x - 8) : x^{2} - 10 x + 16

x^{2} - 10 x + 16 = - 9

Move

9

to the left side

x^{2} - 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

x = 5

The solution to the quadratic equation is:

x = 5

lo g_{64} (8)

4 x^{2} - 5 x - 1 = 0

∣ x + 2 ∣ \geq 4

What are the solutions to the equation (x-2)(x-8)=-9 ?
The solutions to the equation (x-2)(x-8)=-9 are x=5
Find the zeros of (x-2)(x-8)=-9
The zeros of (x-2)(x-8)=-9 are x=5