What are the solutions to the equation x^2+(1/7)^2=1 ?

The solutions to the equation x^2+(1/7)^2=1 are x=(4sqrt(3))/7 ,x=-(4sqrt(3))/7

Find the zeros of x^2+(1/7)^2=1

The zeros of x^2+(1/7)^2=1 are x=(4sqrt(3))/7 ,x=-(4sqrt(3))/7

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x^{2} + (\frac{1}{7})^{2} = 1

x = \frac{4 3}{7}, x = - \frac{4 3}{7}

Decimal Notation

x = 0.98974 \dots, x = - 0.98974 \dots

Solution steps

x^{2} + (\frac{1}{7})^{2} = 1

Expand

x^{2} + (\frac{1}{7})^{2} : x^{2} + \frac{1}{49}

x^{2} + \frac{1}{49} = 1

Move

\frac{1}{49}

to the right side

x^{2} = 1 - \frac{1}{49}

Simplify

1 - \frac{1}{49} : \frac{48}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{48}{49}, x = - \frac{48}{49}

\frac{48}{49} = \frac{4 3}{7}

- \frac{48}{49} = - \frac{4 3}{7}

x = \frac{4 3}{7}, x = - \frac{4 3}{7}

- 10 + 6

4 x^{2} - 5 = 3 x + 4

\frac{d}{4} > 6

4 x^{2} + 5 x - 2 = 0

a + 9 < 5

What are the solutions to the equation x^2+(1/7)^2=1 ?
The solutions to the equation x^2+(1/7)^2=1 are x=(4sqrt(3))/7 ,x=-(4sqrt(3))/7
Find the zeros of x^2+(1/7)^2=1
The zeros of x^2+(1/7)^2=1 are x=(4sqrt(3))/7 ,x=-(4sqrt(3))/7