What is factor 2j^2-3j-2 ?

The solution to factor 2j^2-3j-2 is (2j+1)(j-2)

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factor 2j^2-3j-2

factor

2 j^{2} - 3 j - 2

(2 j + 1) (j - 2)

Solution steps

2 j^{2} - 3 j - 2

Break the expression into groups

= (2 j^{2} + j) + (- 4 j - 2)

Factor out

j

from

2 j^{2} + j : j (2 j + 1)

Factor out

- 2

from

- 4 j - 2 : - 2 (2 j + 1)

= j (2 j + 1) - 2 (2 j + 1)

Factor out common term

2 j + 1

= (2 j + 1) (j - 2)

6 \cdot 5

∣ 2 x - 5 ∣ > 7

- (\frac{1}{5})^{2}

4 x^{2} + 13 x - 12

5 x^{2} \geq 180