What are the solutions to the equation x^2-5x=8 ?

The solutions to the equation x^2-5x=8 are x=(5+sqrt(57))/2 ,x=(5-sqrt(57))/2

Find the zeros of x^2-5x=8

The zeros of x^2-5x=8 are x=(5+sqrt(57))/2 ,x=(5-sqrt(57))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 5 x = 8

x = \frac{5 + 57}{2}, x = \frac{5 - 57}{2}

Decimal Notation

x = 6.27491 \dots, x = - 1.27491 \dots

Solution steps

x^{2} - 5 x = 8

Move

8

to the left side

x^{2} - 5 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 8) = 57

x_{1, 2} = \frac{- ( - 5 ) \pm 57}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 57}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 57}{2 \cdot 1}

x = \frac{- ( - 5 ) + 57}{2 \cdot 1} : \frac{5 + 57}{2}

x = \frac{- ( - 5 ) - 57}{2 \cdot 1} : \frac{5 - 57}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 57}{2}, x = \frac{5 - 57}{2}

0. 6^{2} + 0. 8^{2}

\frac{5}{x y} + \frac{7}{2 x ^{2}}

23 - 2 i

\frac{x + 5}{- 6} > 4

\frac{( 2 x + 7 )}{x - 7} \leq 0

What are the solutions to the equation x^2-5x=8 ?
The solutions to the equation x^2-5x=8 are x=(5+sqrt(57))/2 ,x=(5-sqrt(57))/2
Find the zeros of x^2-5x=8
The zeros of x^2-5x=8 are x=(5+sqrt(57))/2 ,x=(5-sqrt(57))/2