What is the first d/(dt)((m-t)/n) ?

The first d/(dt)((m-t)/n) is -1/n

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d/(dt)((m-t)/n)

\frac{d}{d t} (\frac{m - t}{n})

- \frac{1}{n}

Solution steps

\frac{d}{d t} (\frac{m - t}{n})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{n} \frac{d}{d t} (m - t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{n} (\frac{d m}{d t} - \frac{d t}{d t})

\frac{d m}{d t} = 0

\frac{d t}{d t} = 1

= \frac{1}{n} (0 - 1)

Simplify

= - \frac{1}{n}

\frac{w + 4}{3} - \frac{2 w - 1}{5} = 1

- 5 x + 12 = 5 x + 12

∣ x - 2 ∣^{2} - 2 ∣ x - 2 ∣ - 15 > 0

k^{2} + 17 k + 66

\frac{4}{3} \cdot 4