What are the solutions to the equation (x-3)(4x+9)=0 ?

The solutions to the equation (x-3)(4x+9)=0 are x=3,x=-9/4

Find the zeros of (x-3)(4x+9)=0

The zeros of (x-3)(4x+9)=0 are x=3,x=-9/4

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(x - 3) (4 x + 9) = 0

x = 3, x = - \frac{9}{4}

Decimal Notation

x = 3, x = - 2.25

Solution steps

(x - 3) (4 x + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or 4 x + 9 = 0

Solve

x - 3 = 0 : x = 3

Solve

4 x + 9 = 0 : x = - \frac{9}{4}

The solutions to the quadratic equation are:

x = 3, x = - \frac{9}{4}

\frac{a}{3} + \frac{a}{4} = 6

e^{- \frac{1}{2.25}}

z^{2} - 13 z + 36 = 0

396

\frac{7}{2} - \frac{1}{2}

What are the solutions to the equation (x-3)(4x+9)=0 ?
The solutions to the equation (x-3)(4x+9)=0 are x=3,x=-9/4
Find the zeros of (x-3)(4x+9)=0
The zeros of (x-3)(4x+9)=0 are x=3,x=-9/4