What are the solutions to the equation 9x^2+24x=-19 ?

The solutions to the equation 9x^2+24x=-19 are x=-4/3+i(sqrt(3))/3 ,x=-4/3-i(sqrt(3))/3

Find the zeros of 9x^2+24x=-19

The zeros of 9x^2+24x=-19 are x=-4/3+i(sqrt(3))/3 ,x=-4/3-i(sqrt(3))/3

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9 x^{2} + 24 x = - 19

x = - \frac{4}{3} + i \frac{3}{3}, x = - \frac{4}{3} - i \frac{3}{3}

Solution steps

9 x^{2} + 24 x = - 19

Move

19

to the left side

9 x^{2} + 24 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 9 \cdot 19}{2 \cdot 9}

Simplify

2 4^{2} - 4 \cdot 9 \cdot 19 : 63 i

x_{1, 2} = \frac{- 24 \pm 6 3 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 24 + 6 3 i}{2 \cdot 9}, x_{2} = \frac{- 24 - 6 3 i}{2 \cdot 9}

x = \frac{- 24 + 6 3 i}{2 \cdot 9} : - \frac{4}{3} + i \frac{3}{3}

x = \frac{- 24 - 6 3 i}{2 \cdot 9} : - \frac{4}{3} - i \frac{3}{3}

The solutions to the quadratic equation are:

x = - \frac{4}{3} + i \frac{3}{3}, x = - \frac{4}{3} - i \frac{3}{3}

- 26 + 13 x + 2 > 2 - 13 x

2 x^{2} = 72

- 4 (x + 6) (x + 3)^{2} (x - 2) (x - 3) > 0

6 - 6 x = - 36

a^{2} + 3 0^{2} = 3 4^{2}

What are the solutions to the equation 9x^2+24x=-19 ?
The solutions to the equation 9x^2+24x=-19 are x=-4/3+i(sqrt(3))/3 ,x=-4/3-i(sqrt(3))/3
Find the zeros of 9x^2+24x=-19
The zeros of 9x^2+24x=-19 are x=-4/3+i(sqrt(3))/3 ,x=-4/3-i(sqrt(3))/3