What are the solutions to the equation 2y^2+10y=-9 ?

The solutions to the equation 2y^2+10y=-9 are y=(-5+sqrt(7))/2 ,y=-(5+sqrt(7))/2

Find the zeros of 2y^2+10y=-9

The zeros of 2y^2+10y=-9 are y=(-5+sqrt(7))/2 ,y=-(5+sqrt(7))/2

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2 y^{2} + 10 y = - 9

y = \frac{- 5 + 7}{2}, y = - \frac{5 + 7}{2}

Decimal Notation

y = - 1.17712 \dots, y = - 3.82287 \dots

Solution steps

2 y^{2} + 10 y = - 9

Move

9

to the left side

2 y^{2} + 10 y + 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 \cdot 9}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 \cdot 9 = 27

y_{1, 2} = \frac{- 10 \pm 2 7}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- 10 + 2 7}{2 \cdot 2}, y_{2} = \frac{- 10 - 2 7}{2 \cdot 2}

y = \frac{- 10 + 2 7}{2 \cdot 2} : \frac{- 5 + 7}{2}

y = \frac{- 10 - 2 7}{2 \cdot 2} : - \frac{5 + 7}{2}

The solutions to the quadratic equation are:

y = \frac{- 5 + 7}{2}, y = - \frac{5 + 7}{2}

x^{6} - x^{2}

0 = 0.2 x - 60

(2 f^{4})^{6}

- 4 x + 8 \geq 8

s^{2} + 7 s + 10

What are the solutions to the equation 2y^2+10y=-9 ?
The solutions to the equation 2y^2+10y=-9 are y=(-5+sqrt(7))/2 ,y=-(5+sqrt(7))/2
Find the zeros of 2y^2+10y=-9
The zeros of 2y^2+10y=-9 are y=(-5+sqrt(7))/2 ,y=-(5+sqrt(7))/2