What are the solutions to the equation y^2-2y=0 ?

The solutions to the equation y^2-2y=0 are y=2,y=0

Find the zeros of y^2-2y=0

The zeros of y^2-2y=0 are y=2,y=0

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y^{2} - 2 y = 0

y = 2, y = 0

Solution steps

y^{2} - 2 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 0 = 2

y_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 1}, y_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 1}

y = \frac{- ( - 2 ) + 2}{2 \cdot 1} : 2

y = \frac{- ( - 2 ) - 2}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

y = 2, y = 0

3 x^{2} = - 15 x

\frac{1}{3} \times 9

25 m^{2} - 16 = 0

(\frac{35}{37}) (- \frac{5}{13}) - (\frac{12}{37}) (\frac{12}{13})

What are the solutions to the equation y^2-2y=0 ?
The solutions to the equation y^2-2y=0 are y=2,y=0
Find the zeros of y^2-2y=0
The zeros of y^2-2y=0 are y=2,y=0