What are the solutions to the equation y^2-10y=-20 ?

The solutions to the equation y^2-10y=-20 are y=5+sqrt(5),y=5-sqrt(5)

Find the zeros of y^2-10y=-20

The zeros of y^2-10y=-20 are y=5+sqrt(5),y=5-sqrt(5)

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y^{2} - 10 y = - 20

y = 5 + 5, y = 5 - 5

Decimal Notation

y = 7.23606 \dots, y = 2.76393 \dots

Solution steps

y^{2} - 10 y = - 20

Move

20

to the left side

y^{2} - 10 y + 20 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 20 = 25

y_{1, 2} = \frac{- ( - 10 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 10 ) + 2 5}{2 \cdot 1}, y_{2} = \frac{- ( - 10 ) - 2 5}{2 \cdot 1}

y = \frac{- ( - 10 ) + 2 5}{2 \cdot 1} : 5 + 5

y = \frac{- ( - 10 ) - 2 5}{2 \cdot 1} : 5 - 5

The solutions to the quadratic equation are:

y = 5 + 5, y = 5 - 5

s^{2} + 5 s = 0

3 x^{2} - 5 x - 2 > 0

x^{2} + x - 12 > 0

(x^{2} - 16) - (x - 4) (3 x + 5)

x + x + 1 + x + 2 = 57

What are the solutions to the equation y^2-10y=-20 ?
The solutions to the equation y^2-10y=-20 are y=5+sqrt(5),y=5-sqrt(5)
Find the zeros of y^2-10y=-20
The zeros of y^2-10y=-20 are y=5+sqrt(5),y=5-sqrt(5)