What are the solutions to the equation 0=2x^2-8x+9 ?

The solutions to the equation 0=2x^2-8x+9 are x=2+i(sqrt(2))/2 ,x=2-i(sqrt(2))/2

Find the zeros of 0=2x^2-8x+9

The zeros of 0=2x^2-8x+9 are x=2+i(sqrt(2))/2 ,x=2-i(sqrt(2))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = 2 x^{2} - 8 x + 9

x = 2 + i \frac{2}{2}, x = 2 - i \frac{2}{2}

Solution steps

0 = 2 x^{2} - 8 x + 9

Switch sides

2 x^{2} - 8 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 9}{2 \cdot 2}

Simplify

(- 8)^{2} - 4 \cdot 2 \cdot 9 : 22 i

x_{1, 2} = \frac{- ( - 8 ) \pm 2 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 2 i}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 2 2 i}{2 \cdot 2}

x = \frac{- ( - 8 ) + 2 2 i}{2 \cdot 2} : 2 + i \frac{2}{2}

x = \frac{- ( - 8 ) - 2 2 i}{2 \cdot 2} : 2 - i \frac{2}{2}

The solutions to the quadratic equation are:

x = 2 + i \frac{2}{2}, x = 2 - i \frac{2}{2}

2 + 14 a = - 8 + 9 a

v^{2} + 14 v + 49

\frac{x}{1 - x} < 1

\frac{1}{3} - 5

What are the solutions to the equation 0=2x^2-8x+9 ?
The solutions to the equation 0=2x^2-8x+9 are x=2+i(sqrt(2))/2 ,x=2-i(sqrt(2))/2
Find the zeros of 0=2x^2-8x+9
The zeros of 0=2x^2-8x+9 are x=2+i(sqrt(2))/2 ,x=2-i(sqrt(2))/2