What are the solutions to the equation x^2+10x=-25 ?

The solutions to the equation x^2+10x=-25 are x=-5

Find the zeros of x^2+10x=-25

The zeros of x^2+10x=-25 are x=-5

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x^{2} + 10 x = - 25

x = - 5

Solution steps

x^{2} + 10 x = - 25

Move

25

to the left side

x^{2} + 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

x_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

x = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

x = - 5

The solution to the quadratic equation is:

x = - 5

(\frac{i}{1 - i})^{3}

t^{2} - 43 t + 8 = 0

4 (a + 5) (a - 3) = (4 a + 20) (a - 3)

\frac{2 x ^{\frac{3}{2}}}{3}

(\frac{1}{3 a ^{3}})^{- 4}

What are the solutions to the equation x^2+10x=-25 ?
The solutions to the equation x^2+10x=-25 are x=-5
Find the zeros of x^2+10x=-25
The zeros of x^2+10x=-25 are x=-5