What are the solutions to the equation 4x^2-9x+3=0 ?

The solutions to the equation 4x^2-9x+3=0 are x=(9+sqrt(33))/8 ,x=(9-sqrt(33))/8

Find the zeros of 4x^2-9x+3=0

The zeros of 4x^2-9x+3=0 are x=(9+sqrt(33))/8 ,x=(9-sqrt(33))/8

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4 x^{2} - 9 x + 3 = 0

x = \frac{9 + 33}{8}, x = \frac{9 - 33}{8}

Decimal Notation

x = 1.84307 \dots, x = 0.40692 \dots

Solution steps

4 x^{2} - 9 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

(- 9)^{2} - 4 \cdot 4 \cdot 3 = 33

x_{1, 2} = \frac{- ( - 9 ) \pm 33}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 33}{2 \cdot 4}, x_{2} = \frac{- ( - 9 ) - 33}{2 \cdot 4}

x = \frac{- ( - 9 ) + 33}{2 \cdot 4} : \frac{9 + 33}{8}

x = \frac{- ( - 9 ) - 33}{2 \cdot 4} : \frac{9 - 33}{8}

The solutions to the quadratic equation are:

x = \frac{9 + 33}{8}, x = \frac{9 - 33}{8}

3 = 7.8 + 0 \cdot x + \frac{1}{2} \cdot (- 32.2) \cdot x^{2}

8 < 8 p - 16 < 40

18 m^{2} - 39 m + 18

r^{2} - 10 r + 26 = 0

x^{2} + x < 20

What are the solutions to the equation 4x^2-9x+3=0 ?
The solutions to the equation 4x^2-9x+3=0 are x=(9+sqrt(33))/8 ,x=(9-sqrt(33))/8
Find the zeros of 4x^2-9x+3=0
The zeros of 4x^2-9x+3=0 are x=(9+sqrt(33))/8 ,x=(9-sqrt(33))/8