What are the solutions to the equation -4=x^2+4x ?

The solutions to the equation -4=x^2+4x are x=-2

Find the zeros of -4=x^2+4x

The zeros of -4=x^2+4x are x=-2

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- 4 = x^{2} + 4 x

x = - 2

Solution steps

- 4 = x^{2} + 4 x

Switch sides

x^{2} + 4 x = - 4

Move

4

to the left side

x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

x = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

3 (2 x + 2) > 4 x - 10

\frac{3}{5}

- \frac{2}{3} - \frac{5}{8}

i^{13}

What are the solutions to the equation -4=x^2+4x ?
The solutions to the equation -4=x^2+4x are x=-2
Find the zeros of -4=x^2+4x
The zeros of -4=x^2+4x are x=-2