What are the solutions to the equation -4n^2+6n-16=-5n^2 ?

The solutions to the equation -4n^2+6n-16=-5n^2 are n=2,n=-8

Find the zeros of -4n^2+6n-16=-5n^2

The zeros of -4n^2+6n-16=-5n^2 are n=2,n=-8

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- 4 n^{2} + 6 n - 16 = - 5 n^{2}

n = 2, n = - 8

Solution steps

- 4 n^{2} + 6 n - 16 = - 5 n^{2}

Move

5 n^{2}

to the left side

n^{2} + 6 n - 16 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 16) = 10

n_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 6 + 10}{2 \cdot 1}, n_{2} = \frac{- 6 - 10}{2 \cdot 1}

n = \frac{- 6 + 10}{2 \cdot 1} : 2

n = \frac{- 6 - 10}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

n = 2, n = - 8

∣ x + 7 ∣ = 2

(3 - 6 i)^{2}

2 x^{2} - 7 = 0

- \frac{3}{4} + \frac{5}{8}

\frac{x + 1}{( x - 4 ) ^{2}} \geq 0

What are the solutions to the equation -4n^2+6n-16=-5n^2 ?
The solutions to the equation -4n^2+6n-16=-5n^2 are n=2,n=-8
Find the zeros of -4n^2+6n-16=-5n^2
The zeros of -4n^2+6n-16=-5n^2 are n=2,n=-8