What are the solutions to the equation 24=w^2+5w ?

The solutions to the equation 24=w^2+5w are w=3,w=-8

Find the zeros of 24=w^2+5w

The zeros of 24=w^2+5w are w=3,w=-8

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24 = w^{2} + 5 w

w = 3, w = - 8

Solution steps

24 = w^{2} + 5 w

Switch sides

w^{2} + 5 w = 24

Move

24

to the left side

w^{2} + 5 w - 24 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 24) = 11

w_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 5 + 11}{2 \cdot 1}, w_{2} = \frac{- 5 - 11}{2 \cdot 1}

w = \frac{- 5 + 11}{2 \cdot 1} : 3

w = \frac{- 5 - 11}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

w = 3, w = - 8

9.81 \cdot 2

- 5 (4 x - 2) = - 2 (3 + 6 x)

18 - \frac{324}{17}

x (2 x - 7) \geq 0

7500 (0.143) (\frac{40}{360})

What are the solutions to the equation 24=w^2+5w ?
The solutions to the equation 24=w^2+5w are w=3,w=-8
Find the zeros of 24=w^2+5w
The zeros of 24=w^2+5w are w=3,w=-8