What is 3sqrt(252k^5) ?

The solution to 3sqrt(252k^5) is 18sqrt(7)k^2sqrt(k)

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simplify 3sqrt(252k^5)

simplify

3 252 k^{5}

187 k^{2} k

Solution steps

3 252 k^{5}

Apply radical rule:

ab = a b,

assuming

a \geq 0, b \geq 0

252 k^{5} = 252 k^{5}

= 3252 k^{5}

252 = 67

= 3 \cdot 67 k^{5}

Simplify

k^{5} : k^{2} k

= 3 \cdot 67 k^{2} k

Multiply the numbers:

3 \cdot 6 = 18

= 187 k^{2} k

(a + b) (a + b)

2.5 (6 x - 4) = 10 + 4 (1.5 + 0.5 x)

x^{2} + 4 x + 4 < 0

7 x^{2} + 34 x + 24 = 0

h^{3} + 9 h^{2} - 36 h - 324